在与前端页面交互时，经常需要传递json字符串数据，我们可以使用JSONObject来处理json字符串。
需要导入2个jar包：
fastjson-1.2.2.jar，fastjson-1.2.2-sources.jar
import com.alibaba.fastjson.JSONObject;import org.junit.Test;import java.util.*; 作为测试，先准备几个字符串数据：
private String s1 = " {"AreaName": "北京",n" + " "CityId": 110100,n" + " "NoMarket": false,n" + " "OldCityId": 646,n" + " "Pinyin": "beijing",n" + " "ProvinceId": 110000}"; private String s2 = "[n"+ " {"name":"tom","age":18,"gender":"男"},n"+ " {"name":"lily","age":19,"gender":"女"},n"+ " {"name":"hanmeimei","age":17,"gender":"女"}]"; private String s3 = "{"id":1, "from":"xiaoxin", n" + " "result":[n" + " {"age":18,"gender":"男","name":"tom"},n" + " {"age":19,"gender":"女","name":"lily"},n" + " {"age":17,"gender":"女","name":"hanmeimei"}]}"; private String s4 = "{"age":18,"gender":"男","name":"tom"}"; private String s5 ="[1,2,3,4,5]"; 2.字符串转对象 我们需要使用JSONObject.parse(),JSONObject.parseArray(),JSONObject.parseObject()三个方法来转换json数据，JSONObject.parse()获得后的数据需要强转为JSONObject才能进行下一步操作。
json字符串转为JSONObject对象后,操作数据与map类似，使用get()方法来获取数据，也可以使用getInteger(),getString()…等方法来获取数据。
若要转换为java对象，则需要创建一个有相应字段的类，下例中为User类
@Test public void test1(){ //json字符串转json对象,与map类似 //只写parse,需要强转，写parseObject，则直接得到JSonObject JSonObject jsonObject = (JSONObject) JSONObject.parse(s1); System.out.println(jsonObject);//{"AreaName":"北京","CityId":110100,"NoMarket":false,"OldCityId":646,"Pinyin":"beijing","ProvinceId":110000} //从json对象中获取值 String areaName = jsonObject.getString("AreaName"); System.out.println("----------------"); System.out.println(areaName); System.out.println(jsonObject.getInteger("OldCityId")); System.out.println(jsonObject.get("CityId")); System.out.println("----------------"); //遍历jsonObject jsonObject.forEach((key,value)-> System.out.println(key+"->"+value)); //将字符串转换为java对象 User user = JSON.parseObject(s4, User.class); System.out.println(user); } User类：
public class User { private String name; private int age; private String gender; @Override public String toString() { return "User{" + "name=\'" + name + \'\'\' + ", age=" + age + ", gender=\'" + gender + \'\'\' + \'}\'; } public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } public String getGender() { return gender; } public void setGender(String gender) { this.gender = gender; } public User() { } public User(String name, int age, String gender) { this.name = name; this.age = age; this.gender = gender; }} 转换json数组，需要使用 JSONObject.parseArray()方法，转换为JSONArray类，之后的操作方法与操作ArrayList类似。
@Test public void test2(){ //json对象数组字符串转json对象数组，相当于ArrayList JSonArray jsonS2 = JSONObject.parseArray(s2); System.out.println(jsonS2);//[{"age":18,"gender":"男","name":"tom"},{"age":19,"gender":"女","name":"lily"},{"age":17,"gender":"女","name":"hanmeimei"}] //获取索引为1的值,需要强转为JSonObject JSonObject o1 = (JSONObject)jsonS2.get(0); System.out.println(o1); //遍历// jsonS2.forEach(item-> System.out.println(item)); jsonS2.forEach(System.out::println); //转化为java ArrayList List<User> users = JSON.parseArray(s2, User.class); System.out.println(users); } 转化复杂的json数据，需要一步一步转换，获取相应的数据可以使用getJSonArray(),getJSonObject()方法
@Test public void test3(){ //复杂数据转json对象，与上面的一样 JSonObject objectS3 = JSONObject.parseObject(s3); //拿到result JSonArray JSonArray result = objectS3.getJSonArray("result"); //遍历result result.forEach(System.out::println); //获取指定索引的值 JSonObject o = result.getJSonObject(1); System.out.println(o.getString("name")); //lily //将json数组转换为List List<Integer> numArr = JSON.parseArray(s5, Integer.class); System.out.println(numArr); //将result转换为List对象 List<User> users = JSON.parseArray(objectS3.getJSonArray("result").toJSonString(), User.class); System.out.println(users);//[User{name=\'tom\', age=18, gender=\'男\'}, User{name=\'lily\', age=19, gender=\'女\'}, User{name=\'hanmeimei\', age=17, gender=\'女\'}] } 3.对象转字符串 先准备一个Map和一个List
private HashMap<String, String> map1 = new HashMap<String, String>();private List<String> list1 = new ArrayList<>();private List<User> list2 = new ArrayList<>(); 使用JSONObject.toJSonString()方法来将对象转换为json字符串
@Test public void test1(){ map1.put("apple","新鲜的苹果"); //向集合中添加对象 map1.put("computer","配置优良的计算机"); map1.put("book","堆积成山的图书"); System.out.println(map1); //map对象转json字符串 String s = JSONObject.toJSonString(map1); System.out.println(s); //java对象转json字符串 String s1 = JSONObject.toJSonString(new User("tom", 18, "男")); System.out.println(s1); } 转换数组也是一样：
@Test public void test2(){ Collections.addAll(list1,"tom","18","男"); System.out.println(list1); //ArrayList转json字符串 String s = JSONObject.toJSonString(list1); System.out.println(s); //java对象的ArrayList转json字符串 Collections.addAll(list2,new User("tom",18,"男"),new User("lily",16,"女")); System.out.println(JSONObject.toJSonString(list2)); } 
